Các câu hỏi tương tự
Giai pt \(\left(x+3\right)\sqrt{\left(4-x\right)\left(12+X\right)}=28-x\)
GPT : \(\left(x+3\right)\sqrt{\left(4-x\right)\left(x+12\right)}=28-x\)
Giải phương trình: \(\left(x+3\right)\sqrt{\left(4-x\right)\left(12+x\right)}+x=28\)
giải phương trình:
a. \(\left(x+3\right)\sqrt{\left(4-x\right)\left(12+x\right)}+x=28\)
b. \(x^2\left(x^2+2\right)=4-x\sqrt{2x^2+4}\)
Giải phương trình
1.\(\left(\sqrt{1+x}+\sqrt{1-x}\right)\).\(\left(2+2\sqrt{1-x^2}\right)\)\(=8\)
2.\(\left(x+3\right)\sqrt{\left(4-x\right)\left(12+x\right)}\)\(=28-x\)
Cho hai biểu thức:
A= \(\sqrt{28}-\sqrt{63}+\dfrac{7+\sqrt{7}}{\sqrt{7}}-\sqrt{\left(\sqrt{7}+1\right)}^2\)
B= \(\left(\dfrac{1}{\sqrt{x}+3}+\dfrac{1}{\sqrt{x}-3}\right)\dfrac{4\sqrt{x}+12}{\sqrt{x}}\left(x>0;x\ne9\right)\)
a) Rút gọn A,B
b) Tìm các giá trị của x để A>B?
Help !!!
Mọi người cho em hỏi:left(frac{sqrt{x}}{left[sqrt{x}-3right]left[sqrt{x}+3right]}+frac{2}{sqrt{x}+3}-frac{3}{sqrt{x}-3}right):left(sqrt{x}-3+frac{12-x}{sqrt{x}+3}right)left(frac{sqrt{x}+2left[sqrt{x}-3right]-3left[sqrt{x}+3right]}{left[sqrt{x}-3right]left[sqrt{x}+3right]}right):left(frac{left[sqrt{x}-3right]left[sqrt{x}+3right]+12-x}{sqrt{x}-3}right)left(frac{sqrt{x}+2sqrt{x}-6-3sqrt{x}-9}{left[sqrt{x}+3right]left[sqrt{x}-3right]}right):left(frac{x+3sqrt{x}-3sqrt{x}-9+12-x}{sqrt{x}+3}right)left(...
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Mọi người cho em hỏi:
\(\left(\frac{\sqrt{x}}{\left[\sqrt{x}-3\right]\left[\sqrt{x}+3\right]}+\frac{2}{\sqrt{x}+3}-\frac{3}{\sqrt{x}-3}\right):\left(\sqrt{x}-3+\frac{12-x}{\sqrt{x}+3}\right)\)
\(\left(\frac{\sqrt{x}+2\left[\sqrt{x}-3\right]-3\left[\sqrt{x}+3\right]}{\left[\sqrt{x}-3\right]\left[\sqrt{x}+3\right]}\right):\left(\frac{\left[\sqrt{x}-3\right]\left[\sqrt{x}+3\right]+12-x}{\sqrt{x}-3}\right)\)
\(\left(\frac{\sqrt{x}+2\sqrt{x}-6-3\sqrt{x}-9}{\left[\sqrt{x}+3\right]\left[\sqrt{x}-3\right]}\right):\left(\frac{x+3\sqrt{x}-3\sqrt{x}-9+12-x}{\sqrt{x}+3}\right)\)
\(\left(\frac{-15}{\left[\sqrt{x}+3\right]\left[\sqrt{x}-3\right]}\right):\left(\frac{3}{\sqrt{x}+3}\right)\)
\(\left(\frac{-15}{\left[\sqrt{x}+3\right]\left[\sqrt{x}-3\right]}\right).\left(\frac{\sqrt{x}+3}{3}\right)\)
\(\frac{-5}{\sqrt{x}-3}\)
Giải phương trình:
a) \(\left(x+1\right)\left(x+4\right)=5\sqrt{x^2+5x+28}\)
b) \(\frac{x^2}{\sqrt{3x-2}}-\sqrt{3x-2}=1-x\)
c) \(\left(x+3\right)\sqrt{10-x^2}=x^2-x-12\)
d) \(x^2+3x+1=\left(x+3\right)\sqrt{x^2+1}\)
e) \(3\left(\sqrt{x-2}+2\right)=2x+\sqrt{x+6}\)
GIẢI PHƯƠNG TRÌNH
1. \(16x-13\sqrt{x-1}=9\sqrt{x+1}.\)
2. \(x^2-1=2x\sqrt{x^2-2x}\)
3. \(\left(x+3\right).\sqrt{\left(4-x\right)\left(12+x\right)}=28-x\)
4. \(x+4\sqrt{x+3}+2\sqrt{3-2x}=11\)