`(x-5/6)^2=1/9`
\(\Leftrightarrow\)`(x-5/6)^2 = (1/3)^2`
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{5}{6}=\dfrac{1}{3}\\x-\dfrac{5}{6}=-\dfrac{1}{3}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}+\dfrac{5}{6}\\x=-\dfrac{1}{3}+\dfrac{5}{6}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{6}+\dfrac{5}{6}\\x=-\dfrac{2}{6}+\dfrac{5}{6}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{6}\\x=\dfrac{3}{6}=\dfrac{1}{2}\end{matrix}\right.\)
Vậy `x=7/6` hoặc `x=1/2`
\(\left[{}\begin{matrix}x-\dfrac{5}{6}=\dfrac{1}{3}\\x-\dfrac{5}{6}=-\dfrac{1}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{6}\\x=\dfrac{1}{2}\end{matrix}\right.\)
