Question

\(\left[\frac{2}{3\sqrt{x}}-\frac{2}{\sqrt{x}+1}\left(\frac{\sqrt{x}+1}{3\sqrt{x}}-\sqrt{x}-1\right)\right]:\frac{\sqrt{x}-1}{\sqrt{x}}\)

a/ rút gọn 

Answer 1

Bạn Ngọc Vĩ sai chỗ nhân phân phối nhé. Kq là \(\frac{2\sqrt{x}}{\sqrt{x}-1}\)

Answer 2

ĐKXĐ: tự tìm nhoa

\(\left[\frac{2}{3\sqrt{x}}-\frac{2}{\sqrt{x}+1}.\frac{\sqrt{x}+1}{3\sqrt{x}}+2\left(\sqrt{x}-1\right)\right].\frac{\sqrt{x}}{\sqrt{x}-1}=\left(\frac{2}{3\sqrt{x}}-\frac{2}{3\sqrt{x}}+2\left(\sqrt{x}-1\right)\right).\frac{\sqrt{x}}{\sqrt{x}-1}=2\left(\sqrt{x}-1\right).\frac{\sqrt{x}}{\sqrt{x}-1}=2\sqrt{x}\)