Question

\(\left|\dfrac{1}{2}+\dfrac{-2}{3}\right|\dfrac{24}{7}-\dfrac{4}{7}.\dfrac{3}{5}+\dfrac{2}{5}.\left(\dfrac{-4}{7}\right)\)

Chỉ e vs ạ

Answer 1

\(\left|\dfrac{1}{2}+\dfrac{-2}{3}\right|.\dfrac{24}{7}-\dfrac{4}{7}.\dfrac{3}{5}+\dfrac{2}{5}.\left(\dfrac{-4}{7}\right)\)

\(=\left|-\dfrac{1}{6}\right|.\dfrac{24}{7}+\left(-\dfrac{4}{7}\right).\dfrac{3}{5}+\dfrac{2}{5}.\left(\dfrac{-4}{7}\right)\)

\(=\dfrac{1}{6}.\dfrac{24}{7}+\left(-\dfrac{4}{7}\right).\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\)

\(=\dfrac{4}{7}-\dfrac{4}{7}.1\)

\(=\dfrac{4}{7}-\dfrac{4}{7}\\ =0\)