Question

\(\left(5x-1\right)\left(2x+\frac{1}{3}\right)=0\)

Answer 1

<==> ( 5x - 1)=0            < ===> 5x=1 <===>x=\(\frac{1}{5}\)

hoặc <===> (2x+\(\frac{1}{3}\)) =0        <===> 2x = \(\frac{-1}{3}\) <===> x =\(\frac{-1}{6}\)

vậy x = \(\frac{1}{5}\) hoặc x=\(\frac{-1}{6}\) nha bn !!!

bài này dễ ợt ah !!! cho mik đi :)))

Answer 2

\(\left(5x-1\right)\left(2x+\frac{1}{3}\right)=0\)

\(\Leftrightarrow\hept{\begin{cases}5x-1=0\\2x+\frac{1}{3}=0\end{cases}\Leftrightarrow\hept{\begin{cases}5x=1\\2x=\frac{-1}{3}\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\frac{1}{5}\\x=\frac{-1}{6}\end{cases}}}\)

\(\text{Vậy x }\varepsilon\left(\frac{1}{5};\frac{-1}{6}\right)\)

Answer 3

\(\left(5x-1\right)\left(2x+\frac{1}{3}\right)\)

\(\Rightarrow\orbr{\begin{cases}5x-1=0\\2x+\frac{1}{3}=0\end{cases}}\Rightarrow\orbr{\begin{cases}5x=1\\2x=\frac{-1}{3}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{-1}{6}\end{cases}}}\)

Vậy\(\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{-1}{6}\end{cases}}\)