\(\Leftrightarrow2\left|x\right|-1=6\\ \Leftrightarrow\left|x\right|=\dfrac{5}{2}\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{5}{2}\end{matrix}\right.\)
\(M=\left(216-1^3\right)\cdot\left(216-2^3\right)\cdot\left(216-3^3\right)\cdot...\cdot\left(216-100^3\right)+\left(216\cdot64+216\cdot36\right)\)
\(\left(\frac{1}{216}-\frac{1}{13}\right)\left(\frac{1}{126}-\frac{1}{2^3}\right).....\left(\frac{1}{216}-\frac{1}{10^3}\right)\) Tính biểu thức trên
a.\(3\left(x-1\right)=3\left(y-2\right);4\left(y-2\right)=3\left(z-3\right)v\text{à}2x+3y-z=-250\)
b.\(\frac{x^3}{8}=\frac{y^3}{64}=\frac{z^3}{216}v\text{à}x^2+y^2+z^2=14\)
giải ra giúp mik nha!!!!!!!!!
Tìm x biết
1) \(\left(2x+3\right)\left(x-4\right)+\left(x-5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)
2)\(\left(8x-3\right)\left(3x+2\right)-\left(4x+7\right)\left(x+4\right)=\left(2x+1\right)\left(5x+1\right)-33\)
3)\(6x\left(3x+5\right)-2x\left(9x-2\right)+\left(17-x\right)\left(x-1\right)+x\left(x-18\right)-17x^2=0\)
4)\(\left(x-1\right)\left(x+2\right)-\left(x-3\right)+5x-7=0\)
Giúp mình nha. Camon nhiều
Rút gọn các biểu thức:
\(A=\left(x+3\right)\left(x^2-3x+9\right)-\left(54+x^3\right)\)
\(B=\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
\(C=\left(2x+1\right)^2+\left(1-3x\right)^2+2\left(2x+1\right)\left(3x-1\right)\)
\(D=\left(x-2\right)\left(x^2+2x+4\right)-\left(x+1\right)^3+3\left(x-1\right)\left(x+1\right)\)
Tìm x;y;z
\(\frac{3x}{8}=\frac{3y}{64}=\frac{3z}{216}\) và \(2\left(x^2\right)+2\left(y^2\right)-z^2=1\)
Thu gọn:
\(B=\left(x-3\right)\left(x+3\right)\left(x^2+9\right)-\left(x^2+2\right)\left(x^2-2\right)\)
\(T=\left(x-5\right)\left(x+2\right)+3.\left(x-2\right)\left(x+2\right)-\left(3x-\frac{1}{2}\right)^2+5x^2\)
\(Q=\left(x-2\right)^3+6\left(x-1\right)^2-\left(x+1\right)\left(x^2-x+1\right)\)
Làm đc cái nào thì làm, ko bắt m.n làm cả đâu ! Làm đc hết thì mk cảm ơn!
Tìm x biết :
1. \(\left|2x-1\right|=1-2x\)
2. \(\left|x-1\right|+\left|x-2\right|=1\)
3. \(\left|x+1\right|+\left|x+2\right|=3\)
4. \(\left|x+2\right|+\left|x+3\right|=4\left(x-1\right)-\left|x-1\right|\)
5. \(\left|x+2\right|+\left|x+3\right|=4\left(x+1\right)-\left|x-1\right|\)
Các bạn trình bày cách giải, đúng thì mik tick cho nhé
1)\(\left|x^3-x\right|=\left|2\left(x^2 -x\right)\right|\)
2)\(\left|x^2-1\right|-\left|x+1\right|=0\)
3)\(\left|x^2-3\right|=\left|x-\sqrt{3}\right|\)
