\(\left(2\dfrac{2}{15}\cdot\dfrac{9}{17}\cdot\dfrac{3}{32}\right):\left(-\dfrac{3}{17}\right)\\ =\left(\dfrac{32}{15}\cdot\dfrac{9}{17}\cdot\dfrac{3}{32}\right):\left(-\dfrac{3}{17}\right)\\ =\dfrac{9\cdot3}{15\cdot17}:\left(\dfrac{-3}{17}\right)\\ =\dfrac{9}{5\cdot17}\cdot\dfrac{17}{-3}\\ =\dfrac{-3}{5}\)