/-x-1,5/=2 => -x-1,5=2 hoặc -x-1,5=-2
Xét -x-1,5=2 => -x=3,5 => x=-3,5
Xét -x-1,5=-2 => -x=-0,5 => x=0,5
KL : x=-3,5 hoặc x=0,5
/-x-1,5/=2 => -x-1,5=2 hoặc -x-1,5=-2
Xét -x-1,5=2 => -x=3,5 => x=-3,5
Xét -x-1,5=-2 => -x=-0,5 => x=0,5
KL : x=-3,5 hoặc x=0,5
Bài 1:
a) \(\left(x-1,3\right)^2=9\)
b) \(2^{4-x}=32\)
c) \(\left(x+1,5\right)^2+\left(y-2,5\right)^{10}=0\)
tìm GTNN của: a) \(2\left|3x-1\right|-4\) b) \(1,5+\left|2-x\right|\)
a,\(\left|x+2\right|=\left|-3x+1\right|\)
b,\(\left|x-1,5\right|-\left|3x+2\right|=0\)
c,\(\left|-2+5x\right|=\left|-x^2-2\right|\)
\(\frac{\left(x+1\right)}{1,5}=\frac{3}{2\left(x+1\right)}\)
\(5x-9=5+3x;2^3+0,5x=1,5;\left(5x+1\right)^2=\dfrac{36}{49};\left(\dfrac{-3}{81}\right)^x=-27;2^{x-1}=16\)
tìm x
\(\left|2,5-x\right|=1,3\)
\(\left|x-1,5\right|+\left|2,5-x\right|=0\)
\(\left(x-\frac{1}{2}\right)^2=0\)
\(\left(x-2\right)^2=1\)
\(\left(\text{|}x\text{|}-1,5\right)\left(x+1\right)=0\)
Tìm x; y ; z biết :
\(3,5+\left|x+\dfrac{3}{2}\right|=-1,5.\left(-\sqrt{9}\right)\)
Tìm \(x\in Q\):
\(c,\left|x-1,5\right|+\left|2,5-x\right|\) \(=0\)
\(d,\left|x-\dfrac{4}{5}\right|=\dfrac{3}{4}\)
Bài 1:Rút gọn:
a) A=\(\left|2.x+4,6\right|-2.x+15,4\)
b) B =\(\left|x+7,2\right|-\left|x-1,2\right|\)
c) C =8,5.x - 19,5 - \(\left|1,5.x+4,5\right|\)
d) D =8,5 + x - \(\left|8,5-x\right|\)