Ta có: \(\left(5+\dfrac{3}{16}-\dfrac{2}{5}\right):\dfrac{-6}{7}-\left(\dfrac{3}{5}+1+\dfrac{3}{16}\right)\cdot\dfrac{-7}{6}\)
\(=\left(5+\dfrac{3}{16}-\dfrac{2}{5}-\dfrac{3}{5}-1-\dfrac{3}{16}\right)\cdot\dfrac{-7}{6}\)
\(=3\cdot\dfrac{-7}{6}=\dfrac{-7}{2}\)