\(d.\) \(4\left(0,5-1,5x\right)=-\dfrac{5x-6}{3}.\)
\(\Leftrightarrow2-6x=\dfrac{-5x+6}{3}.\Leftrightarrow6-18x=-5x+6.\)
\(\Leftrightarrow-13x=0.\Leftrightarrow x=0.\)
Vậy \(x=0.\)
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