Bài 3:
a: Ta có: \(\dfrac{3x-1}{x-2}=\dfrac{-1}{3.2}\)
\(\Leftrightarrow9.6x-3.2=-x+2\)
\(\Leftrightarrow10.6x=5.2\)
hay \(x=\dfrac{26}{53}\)
b: Ta có: \(\dfrac{0.6}{2x-1}=\dfrac{2x-1}{2.4}\)
\(\Leftrightarrow\left(2x-1\right)^2=1.44\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=1.2\\2x-1=-1.2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=3.2\\2x=-0.2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1.6\\x=-0.1\end{matrix}\right.\)