Question

làm giúp mình đc câu nào thì đc chiều nay nộp rồi

Answer 1

55: \(\left(-\sqrt{\frac54}\right)^2-\sqrt{\frac94}:\left(-4,5\right)-\sqrt{\frac{25}{16}}\cdot\sqrt{\frac{64}{9}}\)

\(=\frac54-\frac32:\frac{-9}{2}-\frac54\cdot\frac83\)

\(=\frac54+\frac13-\frac{10}{3}=\frac54-3=-\frac74\)

54: \(\frac19\cdot\sqrt{\left(-9\right)^2}-\left|-3^2\right|-14\cdot\sqrt{1-\frac{48}{49}}+\frac{25}{4}\)

\(=\frac19\cdot9-9-14\cdot\sqrt{\frac{1}{49}}+\frac{25}{4}\)

\(=1-9-14\cdot\frac17+\frac{25}{4}=-8-2+\frac{25}{4}=-10+\frac{25}{4}=-\frac{15}{4}\)

53: \(-\frac{5}{\sqrt{196}}-\frac{5}{\left(2\sqrt{21}\right)^2}-\frac{\sqrt{25}}{204}-\frac{\left(\sqrt5\right)^2}{374}\)

\(=-\frac{5}{14}-\frac{5}{84}-\frac{5}{204}-\frac{5}{374}\)

\(=-\frac{5}{2\cdot7}-\frac{5}{7\cdot12}-\frac{5}{12\cdot17}-\frac{5}{17\cdot22}\)

\(=-\left(\frac{5}{2\cdot7}+\frac{5}{7\cdot12}+\frac{5}{12\cdot17}+\frac{5}{17\cdot22}\right)\)

\(=-\left(\frac12-\frac17+\frac17-\frac{1}{12}+\frac{1}{12}-\frac{1}{17}+\frac{1}{17}-\frac{1}{22}\right)=-\left(\frac12-\frac{1}{22}\right)=-\frac{10}{22}=-\frac{5}{11}\)

52: \(\left(\frac{1}{\sqrt{256}}+\frac12-\frac11\right):\left(\frac18-\frac{1}{\sqrt{2^6}}+1\right)\)

\(=\left(\frac{1}{16}-\frac12\right):\left(\frac18-\frac18+1\right)=\frac{1}{16}-\frac12=-\frac{7}{16}\)

51: \(-\frac{10}{\sqrt{121}}\cdot\frac{\sqrt{\left(3+5\right)^2}}{9}+\frac{7}{2\cdot\sqrt{81}}\cdot\frac{5\sqrt4}{11}\)

\(=-\frac{10}{11}\cdot\frac89+\frac{7}{2\cdot9}\cdot\frac{5\cdot2}{11}=\frac{-80}{99}+\frac{35}{99}=\frac{-45}{99}=-\frac{5}{11}\)

50: \(96\left(-\frac12\right)^2+\sqrt{81}\cdot\left|-\frac{16}{9}\right|-1\frac12\cdot\sqrt{\left(-\frac23\right)^2}\)

\(=96\cdot\frac14+9\cdot\frac{16}{9}-\frac32\cdot\frac23=24+16-1=40-1=39\)

49: \(\left|-3\right|:\sqrt{\frac{81}{16}}+\left(-\frac13\right)^3\cdot108+\sqrt{\left(-6\right)^2}:\sqrt{2,25}\)

\(=3:\frac94+\frac{-1}{27}\cdot108+6:1,5\)

\(=\frac43-4+4=\frac43\)

48: \(\left\lbrack\sqrt{\frac49}+\left(-\frac12\right)^2\right\rbrack:0,75+1\frac13\cdot\left|1-\frac{11}{12}\right|\)

\(=\left\lbrack\frac23+\frac14\right\rbrack:\frac34+\frac43\cdot\frac{1}{12}\)

\(=\frac{11}{12}\cdot\frac43+\frac43\cdot\frac{1}{12}=\frac43\left(\frac{11}{12}+\frac{1}{12}\right)=\frac43\)

47: \(\left\lbrack\left(-0,25\right)-\frac34\right\rbrack:\left(-5\right)-3\left(-\frac13\right)^2+\sqrt{\frac{1}{25}}\)

\(=\left\lbrack-\frac14-\frac34\right\rbrack:\left(-5\right)-3\cdot\frac19+\frac15\)

\(=\frac15-\frac13+\frac15=\frac25-\frac13=\frac{6}{15}-\frac{5}{15}=\frac{1}{15}\)

46: \(-\frac{2^3}{9}+\frac49\cdot\left\lbrack-\left(2012\frac27-2012\frac27\right):\left|-\frac{1}{21}\right|\right\rbrack\)

\(=-\frac89+\frac49\cdot\left\lbrack-0:\frac{1}{21}\right\rbrack=-\frac89\)

45: \(\left(\sqrt{\frac14}-1,2\right):1\frac{1}{20}-\left(-\frac52\right)^2+\left|1,25-\frac34\right|\)

\(=\left(\frac12-\frac65\right):\frac{21}{20}-\frac{25}{4}+\left|\frac54-\frac34\right|\)

\(=\frac{-7}{10}\cdot\frac{20}{21}-\frac{25}{4}+\frac24=-\frac23-\frac{23}{4}=-\frac{8}{12}-\frac{69}{12}=-\frac{77}{12}\)

44: \(\sqrt{12^2-44}-\left(1\frac34-2\right)^2+\left(1,5\right)^5:\left(-\frac32\right)^4\)

\(=\sqrt{144-44}-\left(1+\frac34-2\right)^2+\left(1,5\right)^5:\left(1,5\right)^4\)

\(=\sqrt{100}-\left(-\frac14\right)^2+1,5=10-\frac{1}{16}+\frac{24}{16}=10+\frac{23}{16}=\frac{183}{16}\)

43: \(2^3+3\cdot\left(-\frac12\right)^0-\left(\frac12\right)^2\cdot4+\left\lbrack\left(-2\right)^2:\frac12\right\rbrack:8\)

\(=8+3\cdot1-\frac14\cdot4+\left\lbrack4\cdot2\right\rbrack:8\)

=8+3-1+1

=8+3

=11

42: \(\left\lbrack1,5+2\frac12-\left(\sqrt8\right)^2\right\rbrack:\left\lbrack4\frac12-\sqrt{0,25}\right\rbrack-2\frac34\)

\(=\left(1,5+2,5-8\right):\left\lbrack4,5-0,5\right\rbrack-2,75\)

\(=\frac{\left(4-8\right)}{4}-2,75=-1-2,75=-3,75\)