11:
a: \(P=\dfrac{1+\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-1\right)}\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{\sqrt{x}}\)
\(=\dfrac{x-1}{x}\)
b: Để P>1/2 thì P-1/2>0
=>\(\dfrac{x-1}{x}-\dfrac{1}{2}>0\)
=>2x-2-x>0
=>x-2>0
hay x>2
Đúng 0
Bình luận (0)