Question

Làm Giúp mik vs aj

Answer 1

Câu 4:

\(x^2y^2z^2=4\Rightarrow xyz=2\Rightarrow x^3y^3z^3=8\)

\(x^3+y^3-z^3=0\Rightarrow\left[{}\begin{matrix}x^3+y^3=z^3\Rightarrow3x^3+3y^3=3z^3\\y^3-z^3=-x^3\Rightarrow4y^3-4z^3=-4x^3\\x^3-z^3=-y^3\Rightarrow5x^3-5z^3=-5y^3\end{matrix}\right.\)

\(M=\left(3x^3+3y^3\right)\left(4y^3-4z^3\right)\left(5x^3-5z^3\right)=3z^3.\left(-4x^3\right).\left(-5y^3\right)=60.8=480\)

Answer 2

1+1=2