\(A=x^3.\left(-\dfrac{5}{4}x^2y\right).\left(\dfrac{2}{5}x^3y^4\right)\\ =\left(-\dfrac{5}{4}.\dfrac{2}{5}\right).\left(x^3.x^2.x^3\right).\left(y.y^4\right)\\ =-\dfrac{1}{2}.x^8y^5\\ ----\\ B=\left(-\dfrac{3}{4}.x^5y^4\right).\left(xy^2\right).\left(-\dfrac{8}{9}x^2y^5\right)\\ =\left[\left(-\dfrac{3}{4}\right).\left(-\dfrac{8}{9}\right)\right].\left(x^5.x.x^2\right).\left(y^4.y^2.y^5\right)\\ =\dfrac{2}{3}.x^8y^{11}\)
Đúng 2
Bình luận (0)