\(\left|\dfrac{2}{3}+\dfrac{1}{3}:x\right|-\dfrac{5}{6}=1+\dfrac{1}{3}\)
\(\Leftrightarrow\left|\dfrac{1}{3}:x+\dfrac{2}{3}\right|=\dfrac{4}{3}+\dfrac{5}{6}=\dfrac{13}{6}\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{3}:x+\dfrac{2}{3}=\dfrac{13}{6}\\\dfrac{1}{3}:x+\dfrac{2}{3}=-\dfrac{13}{6}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{3}:x=\dfrac{3}{2}\\\dfrac{1}{3}:x=-\dfrac{17}{6}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{9}\\x=-\dfrac{2}{17}\end{matrix}\right.\)