ĐKXĐ: x>=-3/2
\(2x-3\sqrt{2x+3}-7=0\)
=>\(2x+3-3\sqrt{2x+3}-10=0\)
=>\(2x+3-5\sqrt{2x+3}+2\sqrt{2x+3}-10=0\)
=>\(\sqrt{2x+3}\left(\sqrt{2x+3}-5\right)+2\left(\sqrt{2x+3}-5\right)=0\)
=>\(\left(\sqrt{2x+3}-5\right)\left(\sqrt{2x+3}+2\right)=0\)
=>\(\sqrt{2x+3}-5=0\)
=>\(\sqrt{2x+3}=5\)
=>2x+3=25
=>2x=22
=>\(x=\dfrac{22}{2}=11\)