Ta có: \(\left\{{}\begin{matrix}m_X=\dfrac{23}{23+8}.62=46\left(g\right)\\m_Y=62-46=16\left(g\right)\end{matrix}\right.\)
`=>` \(\left\{{}\begin{matrix}M_X=\dfrac{46}{2}=23\left(g/mol\right)\\M_Y=\dfrac{16}{1}=16\left(g/mol\right)\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}X:Natri\left(Na\right)\\Y:Oxi\left(O\right)\end{matrix}\right.\)
Vậy A là Na2O