\(n_{N_2O}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
Gọi số mol Al, Zn là a, b
=> 27a + 65b = 24,9
PTHH: 8Al + 30HNO3 --> 8Al(NO3)3 + 3N2O + 15H2O
______a------------------------------>0,375a
4Zn + 10HNO3 --> 4Zn(NO3)2 + N2O + 5H2O
b-------------------------------->0,25b
=> 0,375a + 0,25b = 0,15
=> a = 0,2 ; b = 0,3
=> \(\left\{{}\begin{matrix}\%Al=\dfrac{0,2.27}{24,9}.100\%=21,69\%\\\%Zn=\dfrac{0,3.65}{24,9}.100\%=78,31\%\end{matrix}\right.\)