\(Al_2O_3+6HCl\xrightarrow[]{}2AlCl_3+3H_2O\)
\(MgO+2HCl\xrightarrow[]{}MgCl_2+H_2O\)
500ml=0,5l
Gọi x, y là số mol \(Al_2O_3,MgO\)
⇒ \(n_{HCl}=6x+2y=0,5.2=1\left(mol\right)\)
Ta có hpt: \(\left\{{}\begin{matrix}102x+40y=18,2\\6x+2y=1\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,1\\y=0,2\end{matrix}\right.\)
\(m_{muối}=m_{AlCl_3}+m_{MgCl_2}=0,2.133,5+0,2.95=45,7\left(g\right)\)