\(m_{H_2O}=1752\cdot1=1752\left(g\right)\)
\(n_{Na_2O}=\dfrac{248}{62}=4\left(mol\right)\)
\(Na_2O+H_2O\rightarrow2NaOH\)
\(4...............................8\)
\(m_{NaOH}=8\cdot40=320\left(g\right)\)
\(m_{dd}=248+1752=2000\left(g\right)\)
\(C\%_{NaOH}=\dfrac{320}{2000}\cdot100\%=16\%\)