Question

help,nhanh vs ạ

Về căn bậc hai nha

a)

Answer 1

 

h: \(\sqrt{5-6\sqrt{5}+9}\)

\(=\sqrt{5-2\cdot\sqrt{5}\cdot3+3^2}\)

\(=\sqrt{\left(3-\sqrt{5}\right)^2}=\left|3-\sqrt{5}\right|=3-\sqrt{5}\)

i: \(\sqrt{\left(3-\sqrt{10}\right)^2}+\sqrt{\left(\sqrt{10}-5\right)^2}\)

\(=\sqrt{10}-3+5-\sqrt{10}\)

=5-3

=2

k: \(x-\sqrt{x^2+8x+16}\)

\(=x-\sqrt{\left(x+4\right)^2}\)

\(=x-\left|x+4\right|\)

\(=x-\left(x+4\right)\)(Vì x>-4)

=x-x-4=-4