Bài 3:
a: Ta có: \(A=3\sqrt{3}+5\sqrt{12}-2\sqrt{27}\)
\(=3\sqrt{3}+10\sqrt{3}-6\sqrt{3}\)
\(=7\sqrt{3}\)
b: ta có: \(B=\left(\sqrt{20}-\sqrt{45}+3\sqrt{5}\right):\sqrt{5}\)
\(=\left(2\sqrt{5}-3\sqrt{5}+3\sqrt{5}\right):\sqrt{5}\)
=2
c: ta có: \(C=\sqrt{5-\sqrt{13+\sqrt{48}}}\)
\(=\sqrt{5-2\sqrt{3}-1}\)
\(=\sqrt{3}-1\)
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