`#3107.101107`
`a)`
`12 - 6x = 0`
`=> 6x = 12`
`=> x = 12 \div 6`
`=> x = 2`
Vậy, `x = 2`
`b)`
`2x + x + 120 = 0`
`=> 3x = -120`
`=> x = -120 \div 3`
`=> x = -40`
Vậy, `x = -40`
`c)`
`x - 5 = 3 - x`
`=> x + x = 3 + 5`
`=> 2x = 8`
`=> x = 8/2 = 4`
Vậy, `x = 4`
`d)`
`7 - 3x = 9 - x`
`=> -3x + x = 9 - 7`
`=> -2x = 2`
`=> x = -1`
Vậy, `x = -1`
`e)`
\(-\dfrac{5}{9}x+1=\dfrac{2}{3}x-10\)
`=> -5/9x - 2/3x = -10 - 1`
`=> -11/9x = -11`
`=> x = -11 \div -11/9`
`=> x = 9`
Vậy, `x = 9`
`f)`
\(2\left(x+1\right)=3+2x\)
`=> 2x + 2 - 2x = 3`
`=> 2x - 2x = 3 - 2`
`=> 0 = 1` (vô lý)
Vậy, `x \in`\(\varnothing\).
help me pls



