Question

hãy viết phân số 31/32 thành tổng các phân số có tử số là 1 nhưng mẫu số khác nhau

Answer 1

31/32 = 1/32 + 30/32 = 1/32+15/16 = 1/32 +1/16+14/16 => 
31/32 = 1/32+1/16+7/8 = 1/32+1/16 +1/8+6/8 => 
31/32=1/32+1/16 +1/8+3/4 = 1/32+1/16+1/8+1/4+2/4 = 1/32+1/16+1/8+1/4+1/2 
Vậy 31/32 = 1/32+1/16+1/8+1/4+1/2

Answer 2

Bạn vào câu hỏi tương tự

Answer 3

Giống 

Answer 4

1/2+1/4+1/8+1/16+1/32

Answer 5

\(\frac{31}{32}\)

= \(\frac{1}{32}+\frac{30}{32}\)

= \(\frac{1}{32}+\frac{15}{16}\)

=\(\frac{1}{32}+\frac{1}{16}+\frac{14}{16}\)

\(\Rightarrow\frac{31}{32}\)

= \(\frac{1}{32}+\frac{1}{16}+\frac{7}{8}\)

= \(\frac{1}{32}+\frac{1}{16}+\frac{1}{8}+\frac{6}{8}\)

\(\Rightarrow\frac{31}{32}\)

=\(\frac{1}{32}+\frac{1}{16}+\frac{1}{8}+\frac{3}{4}\)

= \(\frac{1}{32}+\frac{1}{16}+\frac{1}{8}+\frac{1}{4}+\frac{2}{4}\)

= \(\frac{1}{32}+\frac{1}{16}+\frac{1}{8}+\frac{1}{4}+\frac{1}{2}\)

Vậy \(\frac{31}{32}=\frac{1}{32}+\frac{1}{16}+\frac{1}{8}+\frac{1}{4}+\frac{1}{2}\)

Answer 6

31/32 =  16 + 8 + 4 +2 +1 / 32 = 1/2 + 1/4 + 1/8 + 1/16 + 1/32

Answer 7

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