\(2,A=\tan^225^0\cdot\sin^265^0-5+\left(1+\sin25^0\right)\left(1-\sin25^0\right)\\ A=\dfrac{\sin^225^0}{\cos^225^0}\cdot\cos^225^0-5+1-\sin^225^0\\ A=\sin^225^0-5+1-\sin^225^0=-4\)
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