Question

giups vs a

 

Answer 1

đk x khác 1/2 

\(\dfrac{4x+3}{2x-1}-\dfrac{1}{2}\le0\Leftrightarrow\dfrac{8x+6-2x+1}{2\left(2x-1\right)}\le0\Leftrightarrow\dfrac{6x+7}{2\left(2x-1\right)}\le0\)

TH1 \(\left\{{}\begin{matrix}6x+7\ge0\\2\left(2x-1\right)\le0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ge-\dfrac{7}{6}\\x\le\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow-\dfrac{7}{6}\le x\le\dfrac{1}{2}\)

TH2 : \(\left\{{}\begin{matrix}x\le-\dfrac{7}{6}\\x\ge\dfrac{1}{2}\end{matrix}\right.\)loại