Question

Giups m vs

Answer 1

\(B=\dfrac{\sqrt{x-3-2\sqrt{x-3}+1}}{\sqrt{x-3}-1}=\dfrac{\sqrt{\left(\sqrt{x-3}-1\right)^2}}{\sqrt{x-3}-1}=\dfrac{\sqrt{x-3}-1}{\sqrt{x-3}-1}=1\)