Bài 2:
a: \(=\dfrac{21}{12}+\dfrac{34}{12}-\dfrac{32}{12}=\dfrac{23}{12}\)
b: \(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{2022}-\dfrac{1}{2023}=\dfrac{2022}{2023}\)
c: \(=\dfrac{1}{11}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{21}+...+\dfrac{1}{61}-\dfrac{1}{66}=\dfrac{1}{11}-\dfrac{1}{66}=\dfrac{5}{66}\)
d: \(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{19}-\dfrac{1}{21}=\dfrac{1}{3}-\dfrac{1}{21}=\dfrac{6}{21}=\dfrac{2}{7}\)