Question

Giúp vssssssssssssssssssssssa

Answer 1

\(Q=\dfrac{2a+b}{a+2021}+\dfrac{2b+a}{b+2021}=\dfrac{2a+b}{a+a+b}+\dfrac{2b+a}{b+a+b}\)

\(=\dfrac{2a+b}{2a+b}+\dfrac{2b+a}{2b+a}=1+1=2\)