Câu 1:
\(A=10\sqrt{0,01}-\sqrt{\dfrac{9}{16}}+3\sqrt{49}-\dfrac{1}{6}\sqrt{4}\)
\(=10.\dfrac{1}{10}-\dfrac{3}{4}+3.7-\dfrac{1}{6}.2\)
\(=1-\dfrac{3}{4}+21-\dfrac{1}{3}=\dfrac{251}{12}\)
Câu 2:
Do \(\left|x+2\right|,\left|2y+3\right|\ge0\)
\(\Rightarrow\left\{{}\begin{matrix}x+2=0\\2y+3=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=-2\\y=-\dfrac{3}{2}\end{matrix}\right.\)