Question

Giúp vs ạ 

Answer 1

\(n_{CaCO_3}=\dfrac{50}{100}=0,5\left(mol\right)\)

PTHH: CaCO₃ --t^o--> CaO + CO₂

______0,5----------->0,5

=> m_CaO = 0,5.56 = 28 (g)