Question

Giúp với

Answer 1

\(a,C\%_{KCl}=\dfrac{20}{600}.100\%=3,33\%\\ b,C_{M\left(CuSO_4\right)}=\dfrac{1,5}{0,75}=2M\)

Answer 2

\(C\%_{KCl}=\dfrac{20}{600}.100\%=3,333\%\\ C_{M\left(CuSO_4\right)}=\dfrac{1,5}{0,75}=2M\)