Tóm tắt:
\(R1=9\Omega\)
\(R2=15\Omega\)
\(R3=10\Omega\)
a. \(R=?\Omega\)
b. \(I3=0,4A\Rightarrow I1,I2=?A\)
GIẢI:
a. \(R=R1+\dfrac{R2\cdot R3}{R2+R3}=9+\dfrac{15\cdot10}{15+10}=15\Omega\)
b. \(U23=U2=U3=I3\cdot R3=0,3\cdot10=3V\left(R2//R3\right)\)
\(I2=U2:R2=3:15=0,2A\)
\(I=I1=I23=I2+I3=0,3+0,2=0,5A\left(R1ntR23\right)\)
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