c: \(\dfrac{1}{x^3-1}=\dfrac{1}{\left(x-1\right)\left(x^2+x+1\right)}\)
\(\dfrac{3}{x^2+x+1}=\dfrac{3x-3}{\left(x-1\right)\left(x^2+x+1\right)}\)
\(\dfrac{-2}{x-1}=\dfrac{-2x^2-2x-2}{\left(x-1\right)\left(x^2+x+1\right)}\)
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