b: \(=-\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{7}=\dfrac{1}{7}\)
c: \(=\dfrac{2}{5}+\dfrac{5}{4}-\dfrac{2}{5}+\dfrac{5}{4}-\dfrac{5}{2}=\dfrac{10}{4}-\dfrac{5}{2}=0\)
d: \(=\dfrac{-17}{12}+\dfrac{3}{2}-\dfrac{3}{11}=\dfrac{-17+18}{12}-\dfrac{3}{11}=\dfrac{1}{12}-\dfrac{3}{11}=\dfrac{11-36}{132}=\dfrac{-25}{132}\)