Question

Giúp nhanh nha mn

Answer 1

a, Cực dương --> cực âm nguồn điện

\(R_{td}=R_1+\dfrac{R_2R_3}{R_2+R_3}=22+8=30\Omega\) 

b, \(I_1=\dfrac{U_1}{R_1}=\dfrac{11}{22}=0,5\left(A\right)\) 

\(\Rightarrow I=I_1=I_{23}=0,5A\\ U_{23}=I_{23}R_{23}=\left(12+24\right).8=288V\\ \Rightarrow U=U_1+U_{23}=299V\) 

c, \(I_2=\dfrac{U_{23}}{R_2}=\dfrac{288}{12}=24A\) 

\(I_3=\dfrac{U_{23}}{R_3}=\dfrac{288}{24}=12A\\ U_2=U_3=U_{23}=288\) 

d, \(R_4=\dfrac{U_1}{I_4}=\dfrac{11}{1}=11\Omega\)