a) Ta có hpt: \(\left\{{}\begin{matrix}x+y=100\\35x\%+37y\%=35,4846\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=75,77\\y=24,23\end{matrix}\right.\)
b) \(n_{Cl_2}=\dfrac{5,6}{22,4}=0,25\left(mol\right)\Rightarrow m_{Cl_2}=2.0,25.35,4846=17,7423\left(g\right)\)
c) Số nguyên tử Cl: \(0,25.2.6.10^{23}=3.10^{23}\) (nguyên tử)
Số nguyên tử 35Cl: \(3.10^{23}.75,77=2,2731.10^{23}\) (nguyên tử)
Số nguyên tử 37Cl: \(3.10^{23}-2,2731.10^{23}=7,269.10^{22}\) (nguyên tử)