Question

giúp mk với

Answer 1

\(2.\left(\dfrac{1}{2}.x-\dfrac{1}{3}\right)\)= \(\dfrac{1}{4}\)+ \(\dfrac{3}{2}\)

\(2.\left(\dfrac{1}{2}.x-\dfrac{1}{3}\right)\)= \(\dfrac{7}{4}\)

\(\dfrac{1}{2}.x-\dfrac{1}{3}\)= \(\dfrac{7}{4}\)\(:2\)

\(\dfrac{1}{2}.x-\dfrac{1}{3}\)= \(\dfrac{7}{8}\)

\(\dfrac{1}{2}.x\)= \(\dfrac{7}{8}+\dfrac{1}{3}\)

\(\dfrac{1}{2}.x\)= \(\dfrac{29}{24}\)

x = \(\dfrac{29}{24}:\dfrac{1}{2}\)

\(x=\dfrac{29}{12}\)