Question

giúp mk với chiều nay mk nộp r, cảm ơn mn nhìu

 

Answer 1

a) \(=5x+3x^2-3x-3=3x^2+\left(5-2\right)x-3=3x^2+3x-3\)
b) \(=5^2-x^2-\left(4x^2-4x+1\right)=25-x^2-4x^2+4x-1=-5x^2+4x+24\)
c) \(=\dfrac{\left(x^4-25\right)+2x\left(x^2+5\right)}{x^2+5}=\dfrac{\left(x^2+5\right)\left(x^2+2x-5\right)}{x^2+5}=x^2+2x-5\)