\(n_{Na}=\dfrac{m}{M}=\dfrac{4,6}{23}=0,05\left(mol\right)\\ số.nguyên.tử.là:n.6.10^{23}=0,05.10^{23}=0,3.10^{23}\cdot\left(nguyên.tử\right)\)
\(n_{CO_2}=\dfrac{V_{\left(đktc\right)}}{22,4}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\\ số.phân.tử.là:n.6.10^{23}=0,15.6.10^{23}=0,9.10^{23}\left(phân.tử\right)\)