Question

Giúp mình với

Answer 1

\(a,1\dfrac{2}{3}+x=\dfrac{-11}{3}\\ \Rightarrow\dfrac{5}{3}+x=\dfrac{-11}{3}\\ \Rightarrow x=\dfrac{-11}{3}-\dfrac{5}{3}\\ \Rightarrow x=\dfrac{-16}{3}\\ b,\dfrac{2}{3}+\dfrac{1}{3}:x=\dfrac{3}{4}\\ \Rightarrow\dfrac{1}{3}:x=\dfrac{3}{4}-\dfrac{2}{3}\\ \Rightarrow\dfrac{1}{3}:x=\dfrac{1}{12}\\ \Rightarrow x=\dfrac{1}{3}:\dfrac{1}{12}\\ \Rightarrow x=4\)

Answer 2

a, 2

b,12/12