a) Tần số kiểu gen : P0: 4/15AA: 3/15Aa:8/15aa
Tần số alen:
\(p_A=AA+\dfrac{Aa}{2}=\dfrac{4}{15}+\dfrac{\dfrac{3}{15}}{2}=\dfrac{11}{30}\\ q_a=1-p_A=1-\dfrac{11}{30}=\dfrac{19}{30}\)
b) Cấu trúc di truyền F5:
\(Aa=\dfrac{\dfrac{3}{15}}{2^5}=\dfrac{1}{160};AA=\dfrac{4}{15}+\dfrac{3}{15}.\left(\dfrac{1-\dfrac{1}{32}}{2}\right)=\dfrac{349}{960}\\ aa=\dfrac{8}{15}+\dfrac{3}{15}.\left(\dfrac{1-\dfrac{1}{32}}{2}\right)=\dfrac{605}{960}\\ F5:\dfrac{340}{960}AA:\dfrac{1}{160}Aa:\dfrac{605}{960}aa\)
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