\(A.=\dfrac{83}{42}\)
\(B.=6\dfrac{4}{10}\)
a , \(\dfrac{6}{7}\)+ \(\dfrac{5}{8}\) = \(\dfrac{48}{56}\) +\(\dfrac{30}{56}\) = \(\dfrac{78}{56}\)
b , \(\dfrac{107}{10}-\dfrac{43}{10}\) =\(\dfrac{154}{10}\)
A, \(\dfrac{6}{7}+\dfrac{5}{8}=\dfrac{48}{56}+\dfrac{35}{56}=\dfrac{83}{56}\)
B,\(10\dfrac{7}{10}-4\dfrac{3}{10}=\dfrac{107}{10}-\dfrac{43}{10}=\dfrac{64}{10}\)





