\(6.n_{KNO_3}=0,1.0,5=0,05\left(mol\right)\\ m_{KNO_3}=101.0,05=5,05\left(g\right)\\ 7.n_{CaCl_2}=0,2.0,75=0,15\left(mol\right)\\ m_{CaCl_2}=111.0,15=16,65\left(g\right)\)
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