Question

GIÚP MÌNH VỚI 😥😭👏

Answer 1

a) Ta có: \(f\left(x\right)=2x^2\left(x-1\right)-5\left(x+2\right)-2x\left(x-2\right)\)

\(=2x^3-2x^2-5x-10-2x^2+4x\)

\(=2x^3-4x^2-x-10\)

Bậc là 3

Ta có: \(g\left(x\right)=x^2\left(2x-3\right)-x\left(x+1\right)-\left(3x-2\right)\)

\(=2x^3-3x^2-x^2-x-3x+2\)

\(=2x^3-4x^2-4x+2\)

 

Answer 2

b) Ta có: h(x)=f(x)-g(x)

\(=2x^3-4x^2-x-10-2x^3+4x^2+4x-2\)

\(=3x-12\)

Đặt h(x)=0

nên 3x-12=0

hay x=4