Question

Giúp mình với!!!!!    Trục căn thức ở mẫu 

A = \(\frac{1}{\sqrt[3]{9}-\sqrt[3]{3}+\sqrt[3]{24}-\sqrt[3]{243}+\sqrt[3]{375}}\)

 

Answer 1

\(A=\frac{1}{\sqrt[3]{9}-\sqrt[3]{3}+\sqrt[3]{24}-\sqrt[3]{243}+\sqrt[3]{375}}\)

\(=\frac{1}{\sqrt[3]{9}-\sqrt[3]{3}+\sqrt[3]{8.3}-\sqrt[3]{27.9}+\sqrt[3]{125.3}}\)

\(=\frac{1}{\sqrt[3]{9}-\sqrt[3]{3}+2\sqrt[3]{3}-3\sqrt[3]{9}+5\sqrt[3]{3}}\)

\(=\frac{1}{6\sqrt[3]{3}-2\sqrt[3]{9}}=\frac{1}{2\sqrt[3]{9}.\left(\sqrt[3]{9}-1\right)}\)

\(=\frac{\sqrt[3]{81}.\left(\sqrt[3]{81}+\sqrt[3]{9}+1\right)}{2\sqrt[3]{9}.\left(\sqrt[3]{9}-1\right)\left(\sqrt[3]{81}+\sqrt[3]{9}+1\right).\sqrt[3]{81}}\)

\(=\frac{9\sqrt[3]{9}+9+3\sqrt[3]{3}}{144}\)

p/s: mk k chắc, sai đâu mn ib cho mk nhé

Answer 2

thank bạn nhiều nha