Question

Giúp mình với ah

Answer 1

Bài 1:

1: \(191-\left[10^2-\left(97-94\right)^2\cdot2018^0\right]\)

\(=191-100+3^2\)

=91+9=100

3: \(2345-1000:\left[19-2\cdot\left(21-18\right)^2\right]\)

\(=2345-1000:\left(19-2\cdot9\right)\)

=2345-1000=1345

5: \(\left\{\left[\left(37+13\right):5\right]-45:5\right\}\cdot7\)

\(=\left[50:5-45:5\right]\cdot7=5:5\cdot7=7\)

7: \(2^{11}:\left\{1026-\left[\left(3^4+1\right):41\right]\right\}\)

\(=2^{11}:\left\{1026-82:41\right\}\)

\(=2^{11}:1024=2\)

9: \(12+3\left\{90:\left[39-\left(2^3-5\right)^2\right]\right\}\)

\(=12+3\cdot\left\{90:\left[39-3^2\right]\right\}\)

\(=12+3\cdot\left[90:30\right]=12+3\cdot3=21\)

 Bài 2:

1: \(x^2+1=82\)

=>\(x^2=82-1=81\)

=>\(\left[{}\begin{matrix}x=9\\x=-9\end{matrix}\right.\)

5: \(\left(x-1\right)^3=9^3\)

=>x-1=9

=>x=9+1=10

9: \(\left(x+1\right)^3=27\)

=>\(\left(x+1\right)^3=3^3\)

=>x+1=3

=>x=2

2: \(3^{2x+5}=3^{25}\)

=>2x+5=25

=>2x=20

=>x=10

6: \(3^{2x+1}=27\)

=>\(3^{2x+1}=3^3\)

=>2x+1=3

=>2x=2

=>x=1

10: \(8^{3x+1}=64\cdot8^5\)

=>\(8^{3x+1}=8^2\cdot8^5=8^7\)

=>3x+1=7

=>3x=6

=>x=2

14: \(13^{2x+1}=13^2\cdot13\)

=>\(13^{2x+1}=13^3\)

=>2x+1=3

=>2x=2

=>x=1