Question

Giúp mình với ạ... mình cảm ơn trc nhé

Answer 1

a: \(=\dfrac{\sqrt{28+10\sqrt{3}}}{\sqrt{2}}=\dfrac{5+\sqrt{3}}{\sqrt{2}}=\dfrac{5\sqrt{2}+\sqrt{6}}{2}\)

b: \(=3-\sqrt{6}-2\sqrt{6}+3=6-3\sqrt{6}\)

c: \(=\left(3-\sqrt{7}\right)\cdot\sqrt{16+6\sqrt{7}}\)

\(=\left(3-\sqrt{7}\right)\left(3+\sqrt{7}\right)\)

=9-7

=2