Question

Giúp mình và ạ

Answer 1

\(a,VT=\left(2a+3b-3b+2a\right)\left(2b+3b+3b-2a\right)=4a\cdot6b=24ab=VP\\ b,VT=8a^3-1-8a^3-1=-2=VP\)

Answer 2

a: \(\left(2a+3b\right)^2-\left(3b-2a\right)^2\)

\(=4a^2+12ab+9b^2-9b^2+12ab-4a^2\)

=24ab

b: \(=8a^3-1-8a^3-1\)

=-2

Answer 3

a)\(VT=\left(2a+3b\right)^2-\left(3b-2a\right)^2=4a^2+12ab+9b^2-\left(9b^2-12ab+4a^2\right)=24ab=VP\left(đpcm\right)\)

b)\(VT=\left(8a^3-1\right)-\left(2a+1\right)\left(4a^2-2a+1\right)=\left(8a^3-1\right)-\left(2a+1\right)\left(\left(2a\right)^2-2a\cdot1+1^2\right)=\left(8a^3-1\right)-\left(8a^3+1\right)=-2=VP\left(đpcm\right)\)